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-16y^2+24y+7=0
a = -16; b = 24; c = +7;
Δ = b2-4ac
Δ = 242-4·(-16)·7
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-32}{2*-16}=\frac{-56}{-32} =1+3/4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+32}{2*-16}=\frac{8}{-32} =-1/4 $
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